Solution: One-way Slab Design

1.1 Effective Span

Effective span = Clear span + effective depth

• Assume 20mm clear cover
• Assume 12mm bar diameter
• Effective depth (d) = 200 - 20 - 6 = 174mm
• Effective span = 4000 + 174 = 4174mm

1.2 Loading

Calculate total load:

• Self weight = 0.2 × 25 = 5.0 kN/m²
• Floor finish = 1.0 kN/m²
• Live load = 3.0 kN/m²
• Total load = 9.0 kN/m²
• Factored load = 1.5 × 9.0 = 13.5 kN/m²

2.1 Bending Moment

• Maximum moment = wu × l²/8
• = 13.5 × 4.174²/8
• = 29.4 kN⋅m

2.2 Shear Force

• Maximum shear = wu × l/2
• = 13.5 × 4.174/2
• = 28.2 kN

3.1 Flexural Reinforcement

• Mu = 29.4 kN⋅m
• d = 174mm
• Required As = 485 mm²
• Provide 12mm @ 200mm c/c (565 mm²)

3.2 Distribution Steel

• Minimum As = 0.12% of gross area
• = 240 mm²
• Provide 8mm @ 200mm c/c (251 mm²)